IfSin−1x−x22+x34.....+cos−1x2−x42+x64....=π2for0<x<2 thenx=
12
1
-12
-1
We have sin-1x-x22+x34-...+cos-1x2-x42+x64-....=π2 ⇒x-x22+x34-...=x2-x42+x64-.... ⇒x=x2 ⇒xx-1=0 ⇒x=0,1 Since 0<x<2, ⇒x=1