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If Sn=e1/nn2+2n2e2/n+3n2e3/n++1ne then limnSn is

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detailed solution

Correct option is A

Sn=1n∑k=1n knek/nlimn→∞ Sn=∫01 xexdx=1.


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limn1n+1+1n+2++16n is equal to


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