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If Sn the sum of n terms of A.P, then Sn+3−3Sn+2+3Sn+1−Sn=

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a

2Sn

b

Sn+1

c

3Sn

d

0

answer is D.

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Detailed Solution

Sn+3−3Sn+2+3Sn+1−Sn=Sn+3−Sn+2−2Sn+2−Sn−1+Sn+1−Sn=Tn+3−2Tn+2+Tn+1=Tn+3−Tn+2−Tn+2−Tn+1=d−d=0.

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