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If Sn the sum of n terms of A.P, then Sn+33Sn+2+3Sn+1Sn=

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a
2Sn
b
Sn+1
c
3Sn
d
0

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detailed solution

Correct option is D

Sn+3−3Sn+2+3Sn+1−Sn=Sn+3−Sn+2−2Sn+2−Sn−1+Sn+1−Sn=Tn+3−2Tn+2+Tn+1=Tn+3−Tn+2−Tn+2−Tn+1=d−d=0.


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