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Q.

If  Sn=3+1+3+323!+1+3+32+334!+...........   up to n – terms then the value of   limn→∞Sn  is, (where [.] represent G.I.F)

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a

6

b

7

c

8

d

9

answer is C.

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Detailed Solution

Sn=1+1+32!+1+3+323!......+3n−13−1n!   and 12∑r=1n3r−1r!=12∑3rr!−1r!limn→∞Sn=12e3−1−e−1=12e3−e≈8.59Sn=8
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