Questions
If S1 is the sum of an arithmetic series of ‘n’ odd number of terms and S2, the sum of the terms of the series in odd places, then
detailed solution
Correct option is A
Let the odd number of terms of an arithmetic series be a,a+d,a+2d,a+3d,a+4d,……,a+(n−1)dThen S1=n2{2a+(n−1)d}S2=a+(a+2d)+(a+4d)+… to n+12 terms =n+12×22a+n+12−1×2d =n+14(2a+(n−1)d)∴S1S2=2nn+1Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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