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If S1 is the sum of an arithmetic series of ‘n’ odd number of terms and S2, the sum of the terms of the series in odd places, then
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a
2nn+1
b
nn+1
c
n+12n
d
n+1n
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Correct option is A
Let the odd number of terms of an arithmetic series be a,a+d,a+2d,a+3d,a+4d,……,a+(n−1)dThen S1=n2{2a+(n−1)d}S2=a+(a+2d)+(a+4d)+… to n+12 terms =n+12×22a+n+12−1×2d =n+14(2a+(n−1)d)∴S1S2=2nn+1Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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