If S=x∈R:log0,6⁡0.216log5⁡(5−2x)≤0 then S is equal to

log(0.6)⁡(0.6)3log5⁡(5−2x)≤0⇒ 5−2x≤1⇒ x≥2---iAlso, 5 -2x > 0 ---------(ii)From Eqs. (i) and (ii), we have x∈[2,2.5)