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Questions  

If asecθ+btanθ=c then atanθ+bsecθ2=

a
a2+b2−c2
b
−a2+b2+c2
c
a2+b2+c2
d
a2−b2+c2

detailed solution

Correct option is B

Given asecθ+btanθ=c.Let  atanθ+bsecθ=kSquaring and subtracting on both sides, we get         ∴a2−b2=c2−k2    ∵sec2θ-tan2θ=1         ⇒k2=c2−a2+b2                              =−a2+b2+c2

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