If sec⁡α and cosec⁡α are the roots of x2−px+q+0 then

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p2=q(q−2)

p2=q(q+2)

p2+q2=2q

none of these

answer is B.

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Detailed Solution

sec⁡α+cosec⁡α=p,sec⁡αcosec⁡α=qor sin⁡α+cos⁡αsin⁡αcos⁡α=p and 1sin⁡αcos⁡α=qor 1+2sin⁡αcos⁡αsin2⁡αcos2⁡α=p2or 1+2q1q2=p2or q21+2q=p2 or q(q+2)=p2

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