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Trigonometric Identities
Question

If secα and cosec α are the roots of the equation x2ax+b=0, then 

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Solution

It is given that sec αand cosecα are the roots of the equation x2ax+b=0

 secα+cosecα=a and secαcosecα=b  sinα+cosα=asinαcosα and sinαcosα=1b  sinα+cosα=ab and sinαcosα=1b (sinα+cosα)2=1+2sinαcosα  a2b2=1+23a2=b(b+2)

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