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Questions  

If  sec11+x2+cosec11+y2y+cot11z=π,then

a
x+y+z=0
b
x+y+z=1
c
x+y+z=xyz
d
x+y+z=−xyz

detailed solution

Correct option is C

Let x=tanA,y=tanB,z=tanC.  Then sec-1secA+cosec-1cosecB+cot-1cotC=π ⇒A+B+C=π ⇒tanA+tanB+tanC=tanAtanBtanC ⇒x+y+z=xyz

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