If sec−11+x2+cosec−11+y2y+cot−11z=π,then
x+y+z=0
x+y+z=1
x+y+z=xyz
x+y+z=−xyz
Let x=tanA,y=tanB,z=tanC. Then sec-1secA+cosec-1cosecB+cot-1cotC=π ⇒A+B+C=π ⇒tanA+tanB+tanC=tanAtanBtanC ⇒x+y+z=xyz