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$If \sec (\frac{x - y}{x + y}) = a then \frac{d y}{d x} =$

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Correct option is A

x−yx+y=sec−1⁡ax−y+x+yx−y−x−y=sec−1⁡a+1sec−1⁡a−1−2x2y=sec−1⁡a+1sec−1⁡a−1yx=1−sec−1⁡a1+sec−1⁡axdydx−yx2=0⇒dydx=yx

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If sec⁡x−yx+y=a then dydx=

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$If \sec (\frac{x - y}{x + y}) = a then \frac{d y}{d x} =$