First slide
Binomial theorem for positive integral Index
Question

  If the second term in the expansiona'13+aa-1nis  14a52 then the value of C3   nC2   n is 

Moderate
Solution

 We have, T2=14a52 C1   na113n-1a321=14a52 nan-113+32=14a52 n=14 C3   nC2   n=C3   14C2   14=123=4

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