If the segment of the line between the lines x–y+2=0 and x+y+4=0 is bisected at the origin, equation of the line is

Let the required line meet the given lines at α1,β1 and α2,β2 respectively.then α1−β1,+2=0,   α2+β2+4=0Also α1+α22=0,   β1+β22=0⇒ α2=−1,β2=−3 and α1=1,β1=3Equation of the line passing through (1, 3) and (0, 0) is           y=3x     ⇒  y-3x=0