If the set of factors of a whole number ‘n’ including ‘n’ itself but not ‘1’ is denoted by F(n). If F(16)∩F(40)=F(x) then ‘x’ is
4
8
6
10
F(16)=2,4,8,16,F(40)=2,4,5,8,10,20,40
F(16)∩F(40)={2,4,8}=F(8)
F(x)=F(8)⇒x=8