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Q.

If the sides of ΔABC are 3, 6, 9 units then AG2+BG2+CG2=

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a

42

b

126

c

92

d

69

answer is A.

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Detailed Solution

a=BC=3,b=CA=6,c=AB=9 AG2+BG2+CG2=13[AB2+BC2+CA2]                 =13[9+36+81]=13[126]=42
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If the sides of ΔABC are 3, 6, 9 units then AG2+BG2+CG2=