If θ=3α and sinθ=aa2+b2, the value of the expression acosecα−bsecα is
aa2+b2
2a2+b2
a+b
none of these
acosecα−bsecα=asinα−bcosα=a2+b2sinαcosαaa2+b2cosα−ba2+b2sinα
Now, sin3α=aa2+b2 gives
a2+b2sin3αcosα−cos3αsinαsinαcosα=2a2+b2