If sinα,cosα are the roots of the equation ax2+bx + c = 0, (a≠0),then
a2–b2+2ac = 0
a2+b2+2ac= 0
(a−c)2=b2+c2
none of these
sinα+cosα=−ba,sinαcosα=ca
Now 1=sin2α+cos2α
=(sinα+cosα)2−2sinαcosα
⇒ 1=b2a2−2ca ⇒ a2=b2−2ac
⇒a2−b2+2ac=0