If sin α, cos α are the roots of the equation ax2 + bx + c = 0, then
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a
a2 - b2 + 2ac = 0
b
a - c2 = b2 + c2
c
a2 + b2 - 2ac =0
d
a2 + b2 + 2ac = 0
answer is A.
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Detailed Solution
As given, sin α + cos α = -ba, sin α cos α = caTo eliminate α, we have 1 = sin2 α + cos2 α = (sin α + cos α )2 - 2 sin α cos α = b2a2 - 2ca ⇒a2 - b2 + 2ac = 0