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Q.

If sinθ,cosθ  are the roots of 10x2−qx+5=0 , then q2 =

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a

100

b

200

c

50

d

400

answer is B.

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Detailed Solution

The given equation is 10x2−qx+5=0 sinθ,cosθ  are the roots of given equationSum of the  roots : sinθ+cosθ=q10,      Product of the roots : sinθcosθ=510=12 Take sinθ+cosθ=q10 Squaring on both sides, we getsin2θ+cos2θ+2sinθcosθ=q2100 ⇒1+2(12)=q2100  ⇒q2=200
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If sinθ,cosθ  are the roots of 10x2−qx+5=0 , then q2 =