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If $A = \sin 45^{\circ} + \cos 45^{\circ}$ and $B = \sin 44^{\circ} + \cos 44^{\circ}$ then

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A>B

A=B

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Correct option is A

A=12+12=2sin⁡90∘B=212sin⁡44∘+12cos⁡44∘=2sin⁡45∘+44∘=2sin⁡89∘<2sin⁡90∘=2∴ A>B

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If A=sin⁡45∘+cos⁡45∘ and B=sin⁡44∘+cos⁡44∘ then

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If $A = \sin 45^{\circ} + \cos 45^{\circ}$ and $B = \sin 44^{\circ} + \cos 44^{\circ}$ then