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Q.

If sin(θ/2)=a,cos(θ/2)=b, then (1+sinθ)/(3sinθ+4cosθ+5)=

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a

(a+b)2/(a+3b)2

b

(a+b)2/(3a+b)2

c

(a−b)2/(a+3b)2

d

(a−b)2/(3a−b)2

answer is A.

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Detailed Solution

tanθ/2=a/b, write sinθ and cosθ in term  of tanθ/2
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