If sin(θ/2)=a,cos(θ/2)=b, then (1+sinθ)/(3sinθ+4cosθ+5)=
(a+b)2/(a+3b)2
(a+b)2/(3a+b)2
(a−b)2/(a+3b)2
(a−b)2/(3a−b)2
tanθ/2=a/b, write sinθ and cosθ in term of tanθ/2