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If $\sin θ + \cos e c θ = 2$ , then $\sin^{n} θ + \cos e c^{n} θ$ is equal to

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Correct option is A

We can write sin2θ+1=2sinθ⇒sin2θ−2sinθ+1=0⇒sinθ−12=0⇒sinθ=1⇒cosecθ=1And thus sinnθ+cosecnθ=2

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If sinθ+cosecθ=2 , then sinnθ+cosecnθ is equal to

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If $\sin θ + \cos e c θ = 2$ , then $\sin^{n} θ + \cos e c^{n} θ$ is equal to