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Questions  

If sinα+cosα=m, then sin6α+cos6α is equal to

a
4−3m2−124
b
4+3m2−124
c
3+4m2−124
d
none of these

detailed solution

Correct option is A

sin⁡α+cos⁡α=m⇒1+sin⁡2α=m2⇒sin⁡2α=m2−1Now,sin6⁡α+cos6⁡α=sin2⁡α+cos2⁡α3−3sin2⁡αcos2⁡αsin2⁡α+cos2⁡α=1−3−1+m224=4−3m2−124

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