If Δ=sinθcosϕsinθsinϕcosθcosθcosϕcosθsinϕ−sinθ−sinθsinϕsinθcosϕ0 then
∆ is independent of θ
∆ is independent of ϕ
∆ is a constant
dΔdθθ=π/2=0
Applying C1→C1−(cotϕ)C2, we get
Δ=0sinθsinϕcosθ0cosθsinϕ−sinθ−sinθ/sinϕsinθcosϕ0
=−sinθsinϕ−sinϕsin2θ−cos2θsinϕ [expanding alone C1]
=sinθ, which is independent of ϕ.
Also, dΔdθ=cosθ⇒dΔdθθ=π/2=cos(π/2)=0