Q.

If sin(θ+α)=cos(θ+α) then tanθ=

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a

1+tanα1−tanα

b

1+sinα1−sinα

c

1−tanα1+tanα

d

1+cosα1−cosα

answer is C.

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Detailed Solution

sinθ+αcosθ+α=1⇒ tan(θ+α)=1⇒tanα+tanα=1−tanθtanα⇒tanθ(1+tanα)=1−tanα⇒tanθ=1−tanα1+tanα
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