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If $\frac{3 \sin 2 θ}{5 + 4 \cos 2 θ} = 1$ then the value of $\tan θ$ is equal to

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Correct option is C

6sin⁡θcos⁡θ8cos2⁡θ+1=6tan⁡θ9+tan2⁡θ=1⇒tan2⁡θ−6tan⁡θ+9=0⇒tan⁡θ=3

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If 3sin⁡2θ5+4cos⁡2θ=1 then the value of tan θ is equal to

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If $\frac{3 \sin 2 θ}{5 + 4 \cos 2 θ} = 1$ then the value of $\tan θ$ is equal to