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Questions  

If 15sin4α+10cos4α=6 then the value of 8cosec6α27sec6α is

a
0
b
1
c
-1
d
5

detailed solution

Correct option is A

15tan4⁡α+10=61+tan2⁡α2⇒ 9tan4⁡α−12tan2⁡α+4=0⇒ tan2⁡α=2/3 so 8cosec6⁡α−27sec6⁡α=8(1+3/2)3−27(1+2/3)3=0

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