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Q.

If 15sin4⁡α+10cos4⁡α=6 then the value of 8cosec6⁡α−27sec6⁡α is

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a

0

b

1

c

-1

d

5

answer is A.

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Detailed Solution

15tan4⁡α+10=61+tan2⁡α2⇒ 9tan4⁡α−12tan2⁡α+4=0⇒ tan2⁡α=2/3 so 8cosec6⁡α−27sec6⁡α=8(1+3/2)3−27(1+2/3)3=0
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