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If $2 \sin^{2} ((\frac{π}{2}) \cos^{2} x) = 1 - \cos (πsin 2 x), x \neq (2 n + 1) \frac{π}{2}$ $, n \in I$ then cos 2x is equal to

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Correct option is B

The given equation is equivalent to2sin2⁡(π/2)cos2⁡x=2sin2⁡((π/2)sin⁡2x)or cos2⁡x=sin⁡2xor cos⁡x(cos⁡x−2sin⁡x)=0⇒1−2tan⁡x=0 as cos⁡x≠0,x≠(2n+1)π2or tan⁡x=12⇒cos⁡2x=1−tan2⁡x1+tan2⁡x=35

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If 2sin2⁡π2cos2⁡x=1−cos⁡(πsin⁡2x),x≠(2n+1)π2 ,n∈I then cos 2x is equal to

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If $2 \sin^{2} ((\frac{π}{2}) \cos^{2} x) = 1 - \cos (πsin 2 x), x \neq (2 n + 1) \frac{π}{2}$ $, n \in I$ then cos 2x is equal to