If 2sin2(π/2)cos2x=1−cos(πsin2x),x≠(2n+1)π/2 ,n∈I then cos 2x is equal to
1/5
3/5
4/5
1
The given equation is equivalent to
2sin2(π/2)cos2x=2sin2((π/2)sin2x) or cos2x=sin2x or cosx(cosx−2sinx)=0⇒ 1−2tanx=0 as cosx≠0,x≠(2n+1)π2 or tanx=12⇒ cos2x=1−tan2x1+tan2x=35