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If $\sin θ + cosec θ = 2, then \cos^{2015} θ + {cosec}^{2015} θ$ is equal to

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Correct option is C

sin⁡θ+cosec⁡θ=2⇒sin⁡θ+1sin⁡θ=2→sin⁡θ−1−cosec⁡θ∴cos⁡θ=0. Thus, cos2015⁡θ+cosec2015⁡θ=1

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If sin⁡θ+cosec⁡θ=2, then cos2015⁡θ+cosec2015⁡θ is equal to

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If $\sin θ + cosec θ = 2, then \cos^{2015} θ + {cosec}^{2015} θ$ is equal to