If sin(πcotθ)=cos(πtanθ) then
cot2θ=14,−34
cot2θ=4,43
cot2θ=−34,−14
none of these
We have,
sin(πcotθ)=cos(πtanθ)sin(πcotθ)=sinπ2+πtanθcos(πtanθ)=cos3π2+πcotθ
⇒ πcotθ=π2+πtanθ or, πtanθ=3π2+πcotθ⇒ cotθ−tanθ=12 or, cotθ−tanθ=−32⇒ 1−tan2θ2tanθ=14 or, 1−tan2θ2tanθ=−34⇒ cot2θ=14 or, cot2θ=−34