Q.
If sinβ is geometric mean between sinα and cosα, then cos2β=
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a
2sin2π4−α or 2cos2π4+α
b
2sin2π3−α or 2cos2π3+α
c
sin2π4−α or cos2π4+α
d
sin2π3−α or cos2π3+α
answer is A.
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Detailed Solution
sin2β=sinαcosα,cos2β=1−2sinαcosα=(sinα−cosα)2
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