If sin q and cos q are the roots of the equation ax2 +bx + c = 0, then
(a−c)2=b2−c2
(a−c)2=b2+c2
(a+c)2=b2−c2
(a+c)2=b2+c2
Since sin q and cos q are the roots of the equation ax2 +bx + c = 0
∴ sinθ+cosθ=−baandsinθcosθ=caNow (sinθ+cosθ)2=1+2sinθcosθ∴b2a2=1+2ca=a+2ca∴ b2=a(a+2c)=a2+2ac⇒b2+c2=a2+2ac+c2=(a+c)2⇒(a+c)2=b2+c2