Q.

If sin3⁡θsin⁡(2θ+α)=cos3⁡θcos⁡(2θ+α) and tan⁡2θ=λtan⁡(3θ+α), then the value of λ is _________.

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answer is 2.

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Detailed Solution

We havesin3⁡θsin⁡(2θ+α)=cos3⁡θcos⁡(2θ+α)=k(let)⇒ sin4⁡θsin⁡θsin⁡(2θ+α)=cos4⁡θcos⁡θcos⁡(2θ+α)=k⇒ cos4⁡θ−sin4⁡θ=k[cos⁡θcos⁡(2θ+α)−sin⁡θsin⁡(2θ+α)]⇒ cos⁡2θ=kcos⁡(3θ+α)              …. (1)Also,sin3⁡θcos⁡θsin⁡(2θ+α)cos⁡θ=sin⁡θcos3⁡θsin⁡θcos⁡(2θ+α)=k⇒ sin3⁡θcos⁡θ+sin⁡θcos3⁡θ                =k(sin⁡(2θ+α)cos⁡θ+sin⁡θcos⁡(2θ+α))⇒ sin⁡θcos⁡θsin2⁡θ+cos2⁡θ=ksin⁡(3θ+α)⇒ sin⁡2θ=2ksin⁡(3θ+α)           …… (2)From (1) and (2), we gettan⁡2θ=2tan⁡(3θ+α)
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