If sinθ1sinθ2−cosθ1cosθ2+1=0then the value of tanθ1/2cotθ2/2 is equal to
-1
1
2
-2
sinθ1sinθ2−cosθ1cosθ2=−1 or cosθ1+θ2=1⇒ θ1+θ2=2nπ,n∈1 or θ12+θ22=nπ Thus, tanθ12cotθ22=tanθ12cotnπ−θ12 =−tanθ12cotθ12=−1