If α=sin−132+sin−113 and β=cos−132+cos−113, then
α > β
α = β
α < β
α + β = 2π
From given equations, it can be seen that
α + β = π
Since, sin−1x+cos−1x=π2∀x
Also, α=π3+sin−113<π3+sin−112
as sinθ is increasing in 0, π2
∴α<π3+π6=π2⇒β>π2>α⇒α<β