If α=sin−132+sin−113 and β=cos−132+cos−113, then
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a
α>β
b
α=β
c
α<β
d
α+β=2π
answer is C.
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Detailed Solution
From given equations, it can be seen that α+β=πsince sin−1x+cos−1x=π2∀xAlso, α=π3+sin−113<π3+sin−112as sinθ is increasing in [0,π2]∴ α<π3+π6=π2⇒β>π2>α⇒α<β