If α=sin−132+sin−113 and β=cos−132+cos−113, then
α>β
α=β
α<β
α+β=2π
From given equations, it can be seen that α+β=π
since sin−1x+cos−1x=π2∀x
Also, α=π3+sin−113<π3+sin−112
as sinθ is increasing in [0,π2]
∴ α<π3+π6=π2⇒β>π2>α⇒α<β