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If $(1 - \sin A) (1 - \sin B) (1 - \sin C) = (1 + \sin A)$ $(1 + \sin B) (1 + \sin C)$ , then each sides is equal to

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±cos⁡Acos⁡Bcos⁡C

±sin⁡Asin⁡Bsin⁡C

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detailed solution

Correct option is A

Multiply both the sides by (1−sin⁡A)(1−sin⁡B)(1−sin⁡C) to obtain (1−sin2⁡A) (1−sin2⁡B) (1−sin2⁡C) =cos2⁡Acos2⁡Bcos2⁡C⇒(1−sin⁡A)(1−sin⁡B)(1−sin⁡C)=±cos⁡Acos⁡Bcos⁡C

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If (1−sin⁡A)(1−sin⁡B)(1−sin⁡C)=(1+sin⁡A) (1+sin⁡B)(1+sin⁡C) , then each sides is equal to

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Ready to Test Your Skills?

free study material

If $(1 - \sin A) (1 - \sin B) (1 - \sin C) = (1 + \sin A)$ $(1 + \sin B) (1 + \sin C)$ , then each sides is equal to