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a
tanA=35
b
tanA=53
c
tan A =2
d
tan B =2
answer is A.
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Detailed Solution
Given that,2sinA=3sinB⇒25sinA=15sinB----iand 2cosA=5cosB⇒23cosA=15cosB----iiOn squaring and adding Eqs. (i) and (ii), we get20sin2A+12cos2A=15⇒8sin2A=3⇒sin2A=38⇒cos2A=58∴sin2Acos2A=35⇒tanA=35