If sin A = sin B and cos A = cos B; Aâ B, then
tanâ¡AâB2=0
cosâ¡(A+B)=1
tanâ¡A+B2=0
sinâ¡(AâB)=1/2
sinâ¡A=sinâ¡B and cosâ¡A=cosâ¡BâA=2nÏ+B where n is an integer, nâ 0âAâB2=nÏâtanâ¡AâB2=0