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If $\sin A = \sin B$ and $\cos A = \cos$ $B; A â B,$ then

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tanâ¡AâB2=0

cosâ¡(A+B)=1

tanâ¡A+B2=0

sinâ¡(AâB)=1/2

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detailed solution

Correct option is A

sinâ¡A=sinâ¡B and cosâ¡A=cosâ¡BâA=2nÏ+B where n is an integer, nâ 0âAâB2=nÏâtanâ¡AâB2=0

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If sin A = sin B and cos A = cos B; Aâ B, then

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If $\sin A = \sin B$ and $\cos A = \cos$ $B; A â B,$ then