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$If \sin^{- 1} \frac{1}{3} + \sin^{- 1} \frac{2}{3} = \sin^{- 1} x,$ then the value of x is

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Correct option is B

sin−1⁡13+sin−1⁡23=sin−1⁡x ⇒sin−1⁡131−49+231−19=sin−1⁡x⇒sin−1⁡13⋅53+23⋅83=sin−1⁡x⇒sin−1⁡5+429=sin−1⁡x⇒x=5+429

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If sin−1⁡13+sin−1⁡23=sin−1⁡x, then the value of x is

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$If \sin^{- 1} \frac{1}{3} + \sin^{- 1} \frac{2}{3} = \sin^{- 1} x,$ then the value of x is