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Questions  

If 2sinA2=1+sinA+1sinA, then A2lies between

a
2nπ+π4 and 2nπ+3π4,n∈Z
b
2nπ−π4 and 2nπ+π4,n∈Z
c
2nπ−3π4 and 2nπ−π4,n∈Z
d
−∞ and +∞

detailed solution

Correct option is A

We have,2sin⁡A2=1+sin⁡A+1−sin⁡A⇒2sin⁡A2=(cos⁡A/2+sin⁡A/2)2                                          +(cos⁡A/2−sin⁡A/2)2⇒2sin⁡A/2=|cos⁡A/2+sin⁡A/2|                                                               +|cos⁡A/2−sin⁡A/2|⇒cos⁡A/2+sin⁡A/2≥0 and cos⁡A/2−sin⁡A/2≤0⇒π/4≤A/2≤3π/4 and π/4≤A≤5π/4⇒π/4≤A/2≤3π/4⇒2nπ+π/4≤A/2≤2nπ+3π/4,n∈Z.

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