If sinθ1+sinθ2+sinθ3=3, then cosθ1+cosθ2+cosθ3 is equal to
3
2
1
0
The given relation is satisfied only when
sinθ1=sinθ2=sinθ3=1⇒ cosθ1=cosθ2=cosθ3=0⇒ cosθ1+cosθ2+cosθ3=0