If sinθsinϕ2=tanθtanϕ=3 then which of the following is not true.

We have sinθsinϕ2=tanθtanϕ=3⇒sinθsinϕ.sinθsinϕ=sinθsinϕ.cosϕcosθ⇒sin2θ=sin2ϕ⇒2tanθ1+tan2θ=2tanϕ1+tan2ϕ⇒6tanϕ1+9tan2ϕ=2tanϕ1+tan2ϕ   ∵tanθ=3tanϕ        ⇒tan2ϕ=13⇒               tanϕ=±13⇒               tanθ=±3