If sinθsinϕ2=tanθtanϕ=3 then which of the following is not true.
tanϕ=13
tanϕ=−13
tanθ=3
tanθ=13
We have sinθsinϕ2=tanθtanϕ=3⇒sinθsinϕ.sinθsinϕ=sinθsinϕ.cosϕcosθ⇒sin2θ=sin2ϕ⇒2tanθ1+tan2θ=2tanϕ1+tan2ϕ⇒6tanϕ1+9tan2ϕ=2tanϕ1+tan2ϕ ∵tanθ=3tanϕ ⇒tan2ϕ=13⇒ tanϕ=±13⇒ tanθ=±3