Q.

Ifasin−1x−b cos−1x=c then the value of asin−1x+bcos−1x=

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a

0

b

π2

c

π ab+cb−aa+b

d

π ab+ca−ba+b

answer is D.

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Detailed Solution

Given asin−1x−bcos−1x=c  →1We know that    asin−1x+acos−1x=aπ2  →2Also bsin-1x+bcos-1x=bπ2 →3Now equatioins 2-1⇒ Cos−1x=aπ2−ca+band equations 3+1⇒sin-1x=bπ2+ca+b∴  asin−1x+b cos−1x=πab+ca−ba+b
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