Q.
Ifasin−1x−b cos−1x=c then the value of asin−1x+bcos−1x=
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a
0
b
π2
c
π ab+cb−aa+b
d
π ab+ca−ba+b
answer is D.
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Detailed Solution
Given asin−1x−bcos−1x=c →1We know that asin−1x+acos−1x=aπ2 →2Also bsin-1x+bcos-1x=bπ2 →3Now equatioins 2-1⇒ Cos−1x=aπ2−ca+band equations 3+1⇒sin-1x=bπ2+ca+b∴ asin−1x+b cos−1x=πab+ca−ba+b
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