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Questions  

 If asinx+bcos(x+θ)+bcos(x-θ)=d, then min value of |cosθ|=

a
12bd2−a2
b
12ad2−a2
c
12dd2−a2
d
a2−d2

detailed solution

Correct option is A

asinx+bcos(x+θ)+bcos(x-θ)=d⇒asinx+2bcosθcosx=d|d|≤a2+4b2cos2θ    ∵asinx+bcosx≤a2+b2⇒|cosθ|≥12|b|d2-a2

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