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Questions  

 If asinx+bcos(x+θ)+bcos(x-θ)=d then the minimum value of |cosθ|=

a
12bd2−a2
b
12ad2−a2
c
12dd2−a2
d
0

detailed solution

Correct option is A

We haveasinx+bcos(x+θ)+bcos(x-θ)=d⇒asinx+2bcosxcosθ=d⇒asinx+(2bcosθ)cosx=d⇒|d|≤a2+4b2cos2θ⇒d2≤a2+4b2cos2θ⇒cosθ≥12|b|d2-a2

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