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Questions  

If αsin1x+cos1x+tan1xβ, then

a
α=π4,β=3π4
b
α=−π,β=2π
c
α=0,β=π
d
none of these

detailed solution

Correct option is A

We have,sin−1⁡x+cos−1⁡x=π2 for all x∈[−1,1]Also,−π4≤tan⁡x≤π4 for all x∈[−1,1]∴ −π4+π2≤sin−1⁡x+cos−1⁡x+tan−1⁡x≤π4+π2⇒ π4≤sin−1⁡x+cos−1⁡x+tan−1⁡x≤3π4

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