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If (sin2xcos2x)dx=12sin(2x+k)+C

then

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a
k=π/4
b
k=5π/4
c
k=3π/4
d
none of these

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detailed solution

Correct option is B

Write the given integral as −2∫cos⁡(2x+x/4)dx=−12sin⁡2x+π4+C=12sin⁡2x+5π4+C.


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