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Questions  

 If θ=sin1x+cos1xtan1x0, then the smallest interval in which θ lies, is given by

a
π2≤θ≤3π4
b
−π4≤θ≤0
c
0≤θ≤π4
d
π4≤θ≤π2

detailed solution

Correct option is D

We have, θ=sin−1⁡x+cos−1⁡x−tan−1⁡x=π2−tan−1⁡x=cot−1⁡xSince, 0≤x≤1, therefore π4≤θ≤π2

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